Question

If all the solute is dissolved in diagram $1$, how would heating or cooling the solution cause each of the following changes? (9.3)

a. $2to3$

b. $2to1$

Short answer

(part a) As a function of the temperature dropping. The freezing of the solution causes this change.

(part b) As a reaction of the temperature rise. The boiling of the solution causes this alteration.

Step-by-step solution

Introduction (part a)

The concentration of a solute in a saturated solution, where no more solution can be dissolved, is being used to estimate the magnitude of a substance's solubility in a specific solvent.

Given data (Part a).

(part a) A solution is made when a hard component is combined with water. As the temperature rises, the mobility of the solids solute increases. As a corollary, at a higher temperature, the sample containing more dissolved solute. The solute can be recrystallized when the solution is cooled.

Explanation (Part a).

Image $1$displays the result in the chart below. Image $2$depicts a solution is a mixture some solid, but Image $3$depicts a solution which has a bigger amount of solid than Image $2$.

The transition from solution 2 to liquid 3 shows that the temperature has dropped, causing more solid to develop. The cooling of the regard to the situation this change.

Given data (Part b).

The alterations in the solution are produced by heating or cooling.

Explanation (Part b).

(part b) The transition from solution 2 to water 1 indicates that the solid has decomposed due to the higher temperature. The heating of the regard to the situation this transformation.