Question

An intravenous solution of mannitol is used as a diuretic to increase the loss of sodium and chloride by a patient. If a patient receives $30.0mL$of a $25\%(m/v)$mannitol solution, how many grams of mannitol were given?

Short answer

As an outcome, the patient's necessary mannitol mass is $7.5g.$

Step-by-step solution

Introduction.

Every diuretic works on a separate portion of your kidneys. Some drugs contain and over one kind of diuretic or a diuretics in concert with some other heart rate drug.

Given data.

Using the mass by volume percent equation, determine the mass of mannitol.

$Massvolumepercent(m/v)=\frac{massofsolute}{volumeofsolution}\times 100\%$

Volume of injectable mannitol liquid delivered to the patient$30.0mL$. Mass /volume percent of mannitol solution $25\%(m/v)$, which equals $25mL$, as per the problem.

Explanation.

In the provided phrase, substitute the above values.

$Massvolumepercent(m/v)=\frac{massofsolute}{volumeofsolution}\times 100\%$

$25\%=\frac{massofsolute}{30mL}\times 100\%$

$Massofsolute=7.5g$

As a result, the patient needs $7.5g$of mannitol.