Question

What is the difference between a $10.0\%(v/v)$methanol $\left(C{H}_{4}O\right)$solution and a $10.0\%(m/m)$ methanol solution?

Short answer

The difference between both the methanol solution is,

$10.0\%(v/v)$methanol solution is$10mL$solute in$100mL$ of a solution.

$10.0\%(m/m)$methanol solution indicates $10g$solute in $90g$of water.

Step-by-step solution

Given Information.

The following are the given information to find the difference of the Methanol solution is as follows:

$10.0\%(v/v)$and$10.0\%(m/m)$methanol solution.

Find the Volume percent.

Using the following expression, compute the volume percent.

$\text{Volume percent}(\mathrm{v}/\mathrm{v})=\frac{\text{Solute volume}}{\text{Solution volume}}\times 100\mathrm{\%}$

$10mL$ of solute methanol throughout $100mL$ of solution equals $10.0\%(v/v)$ methanol solution.

Find the Mass percent.

By using following equation, find the mass present.

$\text{Masspercent}(\mathrm{v}/\mathrm{v})=\frac{\text{Solute}\text{mass}}{\text{Solution}\text{mass}}\times 100\mathrm{\%}$

$10g$of solute methanol present in $90g$ of water equals $10.0\%(m/m)$ methanol solution.