Question

Explain the following observations:

a. An open can of soda loses its "fizz" faster at room temperature than in the refrigerator.

b. Chlorine gas in tap water escapes as the sample warms to room temperature.

c. Less sugar dissolves in iced coffee than in hot coffee.

Short answer

(part a) An open can of soda loses its "fizz" faster at room temperature than in the refrigerator because solubility of gas is less at room temperature.

(part b) Chlorine gas in tap water escapes as the sample warms to room temperature because the solubility of gas in water decreases.

(part c) Less sugar dissolves in iced coffee than in hot coffee. The solubility of sugar decreases as the temperature increases.

Step-by-step solution

Introduction (part a).

The solubility of a confined gas is proportional to the fraction of a gas present just above liquid or solution's surface.

Given Information (part a).

To discuss the different data as follows:

An open can of soda loses its "fizz" faster at room temperature than in the refrigerator.

Explanation (part a).

An open can of soda loses its "fizz" faster at room temperature even though gas solubility is lower at room temperature, enabling carbon dioxide to disperse more easily from a can than the refrigerator.

Given Information (part b).

To discuss the different data as follows:

Chlorine gas in tap water escapes as the sample warms to room temperature.

Explanation (part b).

The dissolution rate of a gas in water decreases as the temperature increases. More gas particles have the energy to remove from the solution as the temperature rises. As the specimen warms to room temperature, the chlorine gas inside the tap water escapes.

Given Information (part c).

To discuss the different data as follows:

Less sugar dissolves in iced coffee than in hot coffee.

Explanation (part c).

Sugar solubility decreases significantly as temperature decreases. As a result, iced coffee dissolves less sugar than hot coffee.