Question

Determine whether each of the following solutions will be saturated or unsaturated at ${20}^{\circ }C$:

a. adding $25g$of $KCl$to $100g$of $H_{2}O$

b. adding $11g$of $NaN{O}_3$to $25g$of $H_{2}O$

c. adding $400g$of sugar to $125g$of $H_{2}O$

Short answer

(part a) The following solution $25gofKClto100gof{H}_{2}O$is an unsaturated solution.

(part b) The following solution $11gofNaN{O}_{3}to25gof{H}_{2}O$represents an unsaturated solution.

(part c) The following solution $400gofsugarto125gof{H}_{2}O$and it forms the saturated solution.

Step-by-step solution

Introduction (part a).

Saturated solution: At a specific temperature, the solution cannot dissolve any further solute.

Unsaturated solution: At a specific temperature, a solution can dissolve more solute.

Given Information (part a).

Given:

$25gofKClto100gof{H}_{2}O$

Explanation (part a). 

Adding $25gofKCl$to $100g$of water symbolizes an unsaturated solution because it can dissolve up to $34gofKCl$in $100g$of water at${20}^{\circ }C.$

Given Information (part b). 

Given:

$11gofNaN{O}_{3}to25gof{H}_{2}O$

Explanation (part b). 

At ${20}^{\circ }C,88g$of sodium nitrate melts in $100g$of water, and at this temperature, $22g$of sodium nitrate could indeed dissipate in $25g$of water. So, if $11g$of sodium nitrate is blended with$25g$of water, the result is an unsaturated solution.

Given Information (part c). 

Given:

$400gofsugarto125gof{H}_{2}O$

Explanation (part c).

At ${20}^{\circ }C,100g$of water could really dissipate $203.9g$of sugar, so $125g$of water could disintegrate $253mg$of sugar. Adding$400g$of sugar to$125g$of water at a temperature will result in a saturated solution.