Question

Identify the solute and the solvent in each solution composed of the following:

a. $10.0mL$of acetic acid and $200mL$of water

b. $100.0mL$of water and $5.0g$of sugar

c. $1.0g$of $B{r}_2$and $50.0mL$of methylene chloride$\left(l\right)$

Short answer

(part a) $10.0mL$of Acetic acid is the Solute and $200mL$of water is the Solvent.

(part b) $100mL$of Water is the Solvent and $5.0g$of sugar is the Solute.

(part c) $1.0g$of $B{r}_2$is the Solute and$50.0mL$of Methylene chloride is the Solvent.

Step-by-step solution

Introduction (part a)

A mixture up of two or more types of material in any ratio. There seem to be two main types of mixtures:

• Homogeneous mix

It is also recognized as a solution, so because substance composition is homogeneous.

• Heterogeneous combination

The structure of the material is not consistent throughout this shape of mixture, as well as the component of the mixture is viewable.

Given Information (part a).

$10.0mL$of acetic acid and $200mL$of Water.

To find the Solute and Solvent in the solution.

Explanation (part a).

In the solution; the major component is usually called the solvent, and the minor components are called the solutes.

Hence, $10.0mL$ofacetic acid is solute and$100mL$of water is solvent.

Given Information (part b).

$100mL$ of water and$5.0g$of sugar to find out the Solute and the Solvent.

Explanation (part b).

In a solution, this same major element is usually referred to as the solvent, as well as the minor elements are referred to as the solutes;

Thereby also, sugar is a Solute and water is a Solvent.

Given Information (part c).

$1.0g$of Bromine$\left(B{r}_2\right)$and $50.0mL$of Methylene Chloride.

To find the Solute and Solvent in the given solution.

Explanation (part c).

In a solution, the major component is usually referred to as the solvent, and also the minor components are referred to as the solutes;

Thereby the, Bromine$\left(B{r}_2\right)$ is a Solute and Methylene chloride is a Solvent.