Question

How many liters of a $4.00M\mathrm{NaCl}$solution will provide$25.0\mathrm{g}$ of$\mathrm{NaCl}?$

Short answer

$0.107ml$of a $4.00MNaCl$solution provide$25.0g$of$NaCl$.

Step-by-step solution

Given information

To calculate how much liters of a$4.00\mathrm{MNaCl}$solution will provide$25.0\mathrm{g}$of$NaCl$.

To calculate the moles of NaCl by using the following expression :

Moles of $\mathrm{NaCl}=\frac{\text{mass of}\mathrm{NaCl}}{\text{molar mass of}\mathrm{NaCl}}$

$=\frac{25\mathrm{g}}{58.44\mathrm{g}/\mathrm{mol}}$

$=0.428\mathrm{mol}$

To calculate the volume required by using the following expression :

Volume of $\mathrm{NaCl}=\frac{\text{Moles of}\mathrm{NaCl}}{\text{Molarity of}\mathrm{NaCl}}$

$=\frac{0.428\mathrm{mol}}{4.00\mathrm{M}}$

$=0.107\mathrm{L}$

Therefore, the required volume of$NaCl$solution is$0.107ml$.