Question

How many milliliters of a $1.50MNaBr$solution contain $75.0g$of $NaBr$

Short answer

$486ml$of $NaBr$solution of $1.50MNaBr$solution contains $75.0g$of$NaBr$

Step-by-step solution

Given information

To find how much milliliters of $1.50MNaBr$solution contains $75.0g$of $NaBr$:

Calculate the moles of NaBr by using the following expression :

Moles of $\mathrm{NaBr}=\frac{\text{mass of}\mathrm{NaBr}}{\text{molar mass of}\mathrm{NaBr}}$

$=\frac{75\mathrm{g}}{102.89\mathrm{g}/\mathrm{mol}}$

$=0.729\mathrm{mol}$.

Calculate the volume required by using the following expression :

Volume of$\mathrm{NaBr}=\frac{\text{Moles of}\mathrm{NaBr}}{\text{Molarity of}\mathrm{NaBr}}$

$=\frac{0.729\mathrm{mol}}{1.50\mathrm{M}}$

$=0.486\mathrm{L}\times \left(\frac{1000\mathrm{mL}}{1\mathrm{L}}\right)$

Therefore, the required volume of $NaBr$solution is $486ml$.