Question

What is the molarity of a solution containing $15.6gofKCl$in $274mLofKCl$solution? $(9.4)$

Short answer

The optimizer molarity is$0.77MKCl.$

Step-by-step solution

Given information

Given $15.6gKCl$ in a solution of $274mL=0.274.$

Molarity (moles/L) is required.

Compute molarity using the moles of $KCl$and the quantity of the solution in litres.

$Molarity\left(M\right)=\frac{molesofsolute}{litersofsolution}$

$\mathrm{GKCl}\text{Molar mass}=\frac{\text{moles}KCl}{\text{volume}\left(L\right)}=MKCl\text{solution}$

Explanation.

Factors,

$1moleKCl=74.6gKCl$

$\frac{1moleKCl}{74.6gKCl}and\frac{74.6gKClssss}{1moleKCl}$

Equation,

$molesKCl=15.6\cancel{gmL}\times \frac{1moleKCl}{74.6\cancel{gmL}}=0.21molesKCl$

Divide the molecules of KCl even by quantity in litres to get the molarity.

$Molarity=\frac{0.21molesKCl}{0.274L}=0.77MKCl$