Question

How many liters of $12\%(\mathrm{m}/\mathrm{v})$$\mathrm{KOH}$solution would you need to obtain $75\mathrm{g}$of glucose?

Short answer

The volume of the solution is$0.716\mathrm{L}$.

Step-by-step solution

Given information

The percentage of KOH solution is given which is$12\%$.

Explanation

Molarity is defined as the ratio of concentration over volume.

The percentage of KOH solution is given which is $12\%$$\left(\mathrm{w}/\mathrm{v}\right)$, it means that $12\mathrm{gm}$of $\mathrm{KOH}$is present in $100\mathrm{mL}$of water.

Therefore, for 86 g of KOH, the volume will be

$\frac{86\cancel{\mathrm{gm}}}{12\cancel{\mathrm{gm}}}\times 100=7.166\times 100=716.66\mathrm{mL}$

The unit conversion for mL into L is given as follows:

$716.66\cancel{\mathrm{mL}}\times \frac{1\mathrm{L}}{1000\cancel{\mathrm{mL}}}=0.716\mathrm{L}$

Thus, the volume of the solution is$0.716\mathrm{L}$.