Question

The following compounds contain ions that are required in small amounts by the body. Write the formula for each.

a. Potassium phosphide

b. Copper (II) chloride

c. Iron (III) bromide

d. Magnesium oxide

Short answer

a. The formula for the compound is ${\mathrm{K}}_3\mathrm{P}$.

b. The formula for the compound is ${\mathrm{CuCl}}_2$.

c. The formula for the compound is ${\mathrm{FeBr}}_3$.

d. The formula for the compound is$\mathrm{MgO}$.

Step-by-step solution

Part (a) Given information

To give the formula of the compound Potassium phosphide.

Part (a) Explanation

A binary ionic compound is one that is derived from two elements where one is metal while the other is non-metal.

The naming of a binary ionic compound can be done using the following rules:

1. Firstly, a metallic element is written with its full name.
2. It is then followed by the stem of a non-metallic element and the suffix “-ide” is added after it.

The given compound is Potassium phosphide. It is made up of potassium $\left({\mathrm{K}}^{+}\right)$and phosphide$\left({\mathrm{P}}^{3-}\right)$ ions.

Thus, the formula of the given ionic compound is${\mathrm{K}}_3\mathrm{P}$.

Part (b) Given information

To give the formula of the compound Copper (II) chloride.

Part (b) Explanation

A binary ionic compound is one that is derived from two elements where one is metal while the other is non-metal.

The naming of a binary ionic compound can be done using the following rules:

1. Firstly, a metallic element is written with its full name.
2. It is then followed by the stem of a non-metallic element and the suffix “-ide” is added after it.

The given compound is Copper(II) chloride. It is made up of copper (II) $\left({\mathrm{Cu}}^{2+}\right)$and chloride$\left({\mathrm{Cl}}^{-}\right)$ ions.

Thus, the formula of the given ionic compound is ${\mathrm{CuCl}}_2$.

Part (c) Given information

To give the formula of the compound Iron (III) bromide.

Part (c) Explanation

A binary ionic compound is one that is derived from two elements where one is metal while the other is non-metal.

The naming of a binary ionic compound can be done using the following rules:

1. Firstly, a metallic element is written with its full name.
2. It is then followed by the stem of a non-metallic element and the suffix “-ide” is added after it.

The given compound is Iron(III) bromide. It is made up of Iron(III) $\left({\mathrm{Fe}}^{3+}\right)$and bromide$\left({\mathrm{Br}}^{-}\right)$ ions.

Thus, the formula of the given ionic compound is ${\mathrm{FeBr}}_3$.

Part (d) Given information

To give the formula of the compound Magnesium oxide.

Part (d) Explanation

A binary ionic compound is one that is derived from two elements where one is metal while the other is non-metal.

The naming of a binary ionic compound can be done using the following rules:

1. Firstly, a metallic element is written with its full name.
2. It is then followed by the stem of a non-metallic element and the suffix “-ide” is added after it.

The given compound is Iron(III) bromide. It is made up of magnesium $\left({\mathrm{Mg}}^{2+}\right)$and oxide$\left({\mathrm{O}}^{2-}\right)$ ions.

Thus, the formula of the given ionic compound is $\mathrm{MgO}$.