Question

Write the formula for each of the following compounds.

a. Zinc bromide

b. Iron (III) sulfide

c. Manganese (IV) oxide

d. Chromium (III) iodide

e. Lithium nitride

f. Gold (I) oxide

Short answer

a. The formula of the compound is ${\mathrm{ZnBr}}_2$.

b. The formula of the compound is ${\mathrm{Fe}}_2{\mathrm{S}}_3$.

c. The formula of the compound is ${\mathrm{MnO}}_2$.

d. The formula of the compound is ${\mathrm{CrI}}_3$.

e. The formula of the compound is ${\mathrm{LiN}}_3$.

f. The formula of the compound is Au₂O.

Step-by-step solution

Part (a) Given information

To give the formula of the compound Zinc bromide.

Part (a) Explanation

A binary ionic compound is one that is derived from two elements where one is metal while the other is non-metal.

The naming of a binary ionic compound can be done using the following rules:

1. Firstly, a metallic element is written with its full name.
2. It is then followed by the stem of a non-metallic element and the suffix “-ide” is added after it.

The given compound is Zinc bromide. It is made up of zinc $\left(Z{n}^{2+}\right)$and bromide$\left(B{r}^{-}\right)$ions.

Thus, the formula of the given ionic compound is$\mathrm{ZnBr}$
.

Part (b) Given information

To give the formula of the compound Iron (II) sulfide .

Part (b) Explanation

A binary ionic compound is one that is derived from two elements where one is metal while the other is non-metal.

The naming of a binary ionic compound can be done using the following rules:

1. Firstly, a metallic element is written with its full name.
2. It is then followed by the stem of a non-metallic element and the suffix “-ide” is added after it.

The given compound is Iron (III) sulfide . It is made up of iron (III) $\left({\mathrm{Fe}}^{3+}\right)$and sulfide $\left(S^{2-}\right)$ions.

Thus, the formula of the given ionic compound is${\mathrm{Fe}}_2{\mathrm{S}}_3$.

Part (c) Given Information

To give the formula of the compound Manganese (IV) oxide.

Part (c) Explanation

A binary ionic compound is one that is derived from two elements where one is metal while the other is non-metal.

The naming of a binary ionic compound can be done using the following rules:

1. Firstly, a metallic element is written with its full name.
2. It is then followed by the stem of a non-metallic element and the suffix “-ide” is added after it.

The given compound is Manganese (IV) oxide. It is made up of Manganese(IV) ion $\left({\mathrm{Mn}}^{4+}\right)$and oxide ion $\left({\mathrm{O}}^{2-}\right)$.

Thus, the formula of the given ionic compound is${\mathrm{MnO}}_2$.

Part (d) Given information

To give the formula of the compound Chromium (III) iodide .

Part (d) Explanation

A binary ionic compound is one that is derived from two elements where one is metal while the other is non-metal.

The naming of a binary ionic compound can be done using the following rules:

1. Firstly, a metallic element is written with its full name.
2. It is then followed by the stem of a non-metallic element and the suffix “-ide” is added after it.

The given compound is Chromium (III) iodide. It is made up of chromium ion $\left({\mathrm{Cr}}^{3+}\right)$and iodide ions $\left({\mathrm{I}}^{-}\right)$.

Thus, the formula of the given ionic compound is${\mathrm{CrI}}_3$.

Part (e) Given information

To give the formula of the compound Lithium nitride.

Part (e) Explanation

A binary ionic compound is one that is derived from two elements where one is metal while the other is non-metal.

The naming of a binary ionic compound can be done using the following rules:

1. Firstly, a metallic element is written with its full name.
2. It is then followed by the stem of a non-metallic element and the suffix “-ide” is added after it.

The given compound is Lithium nitride. It is made up of lithium ion $\left({\mathrm{Li}}^{+}\right)$and nitride ion $\left({\mathrm{N}}^{3-}\right)$.

Thus, the formula of the given ionic compound is${\mathrm{LiN}}_3$.

Part (f) Given information

To give the formula of the compound Gold (I) oxide.

Part (f) Explanation

A binary ionic compound is one that is derived from two elements where one is metal while the other is non-metal.

The naming of a binary ionic compound can be done using the following rules:

1. Firstly, a metallic element is written with its full name.
2. It is then followed by the stem of a non-metallic element and the suffix “-ide” is added after it.

The given compound is Gold (I) oxide. It is composed of Gold (I) ion $\left({\mathrm{Au}}^{+}\right)$and oxide ion $\left({\mathrm{O}}^{2-}\right)$ion.

Thus, the formula of the given ionic compound is${\mathrm{Au}}_2\mathrm{O}$.