Question

The activity of C-14 in a 70kg human body is estimated to be 3.7 kBq. What is this activity in microcuries?

Short answer

The activity is$1\times {10}^{-4}\text{mCi}$

Step-by-step solution

Given Information

The activity of C-$14$in a $70$kg human body is estimated to be $3.7$ kBq.

Explanation

Converting to mCi,

$3.7\mathrm{kBq}\times \frac{1\mathrm{mCi}}{37000\mathrm{kBq}}=1\times {10}^{-4}\mathrm{mCi}$

Hence the activity is$1\times {10}^{-4}\text{mCi}$