Question

The activity of$\mathrm{C}-14$in a $70$-kg human body is estimated to be$3.7\mathrm{kBq}$. What is this activity in microcuries? (5.3)

Short answer

The microcuries' activity$0.099$ Mino Arie

Step-by-step solution

Step 1:Introduction

What exactly is microcurie? (unit) A microcurie is a unit of radioactivity measurement. A microcurie (Ci) is a non-SI (non-System International) radioactivity measurement unit. Given data is the activity of$14\mathrm{C}$in a $70-\mathrm{kg}$human body is estimated to be$3.7\mathrm{kBq}$.

To find activity in microcuries

Step 2:Given data

Given data is The activity of $14\mathrm{C}$in a$70-\mathrm{kg}$human body is estimated to be $3.7\mathrm{kBq}$.

To find activity in microcuries

Step 3:Explanation

$Bv=2.7\times {10}^{-11}$

$1KBV=2.7\times {10}^{-11}\times {10}^3\text{Giuni}$

$=2.7\times {10}^{-8}\mathrm{cmis}$

$$\begin{gathered} lK{B}_q=2.7\times {10}^{-8}\times {10}^{6}a \\ =2.7\times {10}^{-2}\text{mino mini.} \end{gathered}$$

$$\begin{gathered} 3.7kBv=3.7\times 2.7\times {10}^{-2} \\ =0.099\text{mino arie} \end{gathered}$$

The microcuries' activity $0.099$ Mino Arie