Question

How is ${\mathrm{FADH}}_2$oxidized in electron transport?

Short answer

The ${\mathrm{FADH}}_2$get oxidized in electron transport by interacting with $\mathrm{CoQ}$in Complex$\mathrm{II}$

Step-by-step solution

Given information

We need to find the way by which${\mathrm{FADH}}_2$get oxidized while electron transfer

Explanation

When $FAD{H}_2$interacts with $\mathrm{CoQ}$in Complex $\mathrm{II}$, it is immediately oxidized. $\mathrm{CoQ}$absorbs electrons and hydrogen ions directly from ${\mathrm{FADH}}_2$, which was formed in the citric acid cycle after the production of fumarate from succinate via oxidation by succinate dehydrogenase. After absorbing electrons and hydrogen ions from ${\mathrm{FADH}}_2$, $\mathrm{CoQ}$is reduced to ${\mathrm{CoQH}}_2$, while ${\mathrm{FADH}}_2$is oxidized to $\mathrm{FAD}$after releasing electrons and hydrogen ions. Later oxidative pathways,$\mathrm{FAD}$ will be employed in other oxidative reactions.