Question

Give the abbreviation for each of the following:

(a) Reduced form of $NAD$.

(b) Oxidized form of $FAD{H}_2$.

Short answer

(a) The abbreviation of reduced form of $NAD$is $NADH$.

(b) The abbreviation of oxidized form of $FAD{H}_{2_{}}$is$FAD$.$FAD{H}_2$

Step-by-step solution

Part (a) Step 1: Given Information

We need to find the abbreviation of reduced form of$NAD$.

Part (a) Step 2: Explanation

The abbreviation of reduced form of $NAD$is $NADH$. we know that $NAD$is exists in two forms: An oxidized and reduced form, abbreviated and NAD andNADH respectively .

Part (b) Step 1: Given Information

We need to find the abbreviation of oxidized form of$FAD{H}_{2_{{}_{}}}$.

Part (b) Step 2: Explanation

The abbreviation of oxidized form of $FAD{H}_2$is $FAD$. it in its fully oxidized form, or quinone Form, accepts two electrons and two protons to become The $FADH$can be formed by Reduction of $FAD$.