Question

If you want to lose $1lb$of "body fat," which is $15\%$water, how many kilocalories do you need to expend?

Short answer

As a result, if a person wishes to shed $1$pound of fat, which is $15$percent water, he or she must lose $3500$kcal.

Step-by-step solution

Given Information.

The Following are the given information as:

Body fat$=1lb$

water present in body$=15\%$

To find the Kilocalories found in body

Explanation 

The proportion is calculated as follows: $15$mass units of water contains $100$mass units of fat.

As a result, $1lb$of body fat comprises $0.85lb$of fat, which is $15$percent water. Then, $1g$of fat contains $9Kcal$,

Hence the equation is same.

$1gFat=9Kcal$

Find the Kilocalories.

We're given a weight in pounds, which we must convert to grammes. Egalitarianism exists.

$1\mathrm{lb}=454\mathrm{g}$

These are the factors of conversion

$\frac{1\mathrm{lb}}{454\mathrm{g}}\text{and}\frac{454\mathrm{g}}{1\mathrm{lb}}$

As a result, using the relevant conversion factors, the number of kilocalories that must be lost can be computed.

$0.85\mathrm{tbfat}\times \frac{454\mathrm{gfat}}{1\mathrm{fbfat}}\times \frac{9\mathrm{kcal}}{1\mathrm{gfat}}=3500\mathrm{kcal}$