Question

Identify the group number in the periodic table of $X$, a representative element, in each of the following ionic compounds:$(6.2)$

a.$X_2{O}_3$

b.$X_{2}S{O}_3$

c.$N{a}_{3}X$

Short answer

a. The group number is$3A\left(13\right)$.

b. The group number is $1A\left(1\right)$.

c. The group number is$5A\left(15\right)$.

Step-by-step solution

Part (a) step 1: Given Information

We need to identify the group number of$X_2{O}_3$.

Part (a) step 2: Simplify

Consider:$X_2{O}_3$

ion of oxygen $\left(O\right)‐‐‐O^{2-}$say change of $X$is $x$then by charge balance -

$$\begin{gathered} 2x+3(2-)=0 \\ x=+3 \end{gathered}$$

Therefore, ion of $x‐‐‐X^{3+}$

Here, three electrons are donated to achieve octect so group is$3A\left(13\right)$.

Part (b) step 1: Given Information

We need to identify the group number of$X_{2}S{O}_3$.

Part (b) step 2: Simplify

Consider: $X_{2}S{O}_3$

ion of Sulfite $‐‐‐{So}_3^{2-}$charge of $X$is $x$then by charge balance -

$$\begin{gathered} 2x+(2-)=0 \\ x=1+ \end{gathered}$$

Therefore, the ion of $x‐‐‐X^{+}$

Here,

An electron donated to achieve octect so group isrole="math" localid="1652437478196" $1A\left(1\right)$.

Part (c) step 1: Given Information

We need to identify the group number of$N{a}_{3}X$.

Part (c) step 2: Simplify

Consider: $N{a}_{3}X$

ion of Sodium $\left(Na\right)$$‐‐‐N{a}^{+}$charge of $X$is $x$then by charge balance -

$$\begin{gathered} x+3\left(1+\right)=0 \\ x=3- \end{gathered}$$

Therefore, the ion of $x‐‐‐X^{3-}$

Three electron accepted to achieve octect so the group is$5A\left(15\right)$.