Question

Write the correct ionic formula for the compound formed between each of the following pairs of ions:

a. $P^{3-}$and ${\mathrm{Cl}}^{-}$

b. ${\mathrm{Ca}}^{2+}$and ${\mathrm{S}}^{2-}$

c. ${\mathrm{Li}}^{+}$and $S^{2-}$

d. ${\mathrm{Rb}}^{+}$and ${\mathrm{P}}^{3-}$

e.$C{s}^{{+}^{}}$and $I^{-}$

Short answer

a.is the correct ionic formula for the chemical.

b. The compound's correct ionic formula is .

c.is the proper ionic formula for the chemical.

d. is the right ionic formula for the compound.

e. The compound's correct ionic formula is

Step-by-step solution

Given information (part a)

Write the correct ionic formula for the compound formed between each of the following pairs of ions:

a. ${\mathrm{Al}}^{3+}$and ${\mathrm{Cl}}^{-}$

Explanation (part a)

(part a) The charge on the ${\mathrm{Al}}^{3+}$ion is $3+$while the charge on the ${\mathrm{Cl}}^{-i}$ion is $1$-. One ${\mathrm{Al}}^3$ion and three ${\mathrm{Cl}}^{-}$ions are used to balance the charge $(3+)+3\times (1-)=0$. Write the positive ion first, then the negative ion in the ionic formula. ${\mathrm{AlCl}}_3$is the correct ionic formula for the chemical.

Given Information (part b)

Write the correct ionic formula for the compound formed between each of the following pairs of ions:

b. ${\mathrm{Ca}}^{2+}$and ${\mathrm{S}}^{2-}$

Explanation (part b)

The charge on the ${\mathrm{Ca}}^{2+}$ion is $2+$while the charge on the ${\mathrm{s}}^2$ion is $2-$.${\mathrm{S}}^{2-}$with three ${\mathrm{Ca}}^{2+}$ions and two$(2+)+(2-)=0$ions. Write the positive ion first, then the negative ion in the ionic formula. The compound's correct ionic formula is $\mathrm{CaS}$.

Given information (part c)

Write the correct ionic formula for the compound formed between each of the following pairs of ions:

c. ${\mathrm{Li}}^{+}$and ${\mathrm{S}}^{2-}$

Step  6 : Explanation (part c)

The fee for ${\mathrm{Li}}^{+}$ion is $1$, but the fee for ${\mathrm{S}}^{2-}$is 2. Two ${\mathrm{Li}}^{+}$ions and one${\mathrm{S}}^{2-}$ions $2\times (1+)+(2-)=0$ions are used to balance the charge. Write the positive ion first, then the negative ion, in the ionic formula.${\mathrm{Li}}_2\mathrm{S}$is the proper ionic formula for the chemical.

 : Given information (part d)

Write the correct ionic formula for the compound formed between each of the following pairs of ions:

d. ${\mathrm{Rb}}^{+}$and ${\mathrm{P}}^{3-}$

Expanation (part d)

The charge on the ion is $1+$, while the charge on the ${\mathrm{p}}^{3-}$ionis $3-$. Three ${\mathrm{Rb}}^{+}$ions and one ${\mathrm{P}}^3$ion are used to balance the charge $3\times (1+)+(3-)=0$. Write the positive ion first, then the negative ion in the ionic formula. ${\mathrm{Rb}}_3\mathrm{P}$is the right ionic formula for the compound.

Given information (part e) 

Write the correct ionic formula for the compound formed between each of the following pairs of ions:

e. ${\mathrm{Cs}}^{+}$and ${\mathbf{I}}^{\mathbf{-}}$

Explanation (part e)

The fee for ${\mathrm{Cs}}^{+}$ion is $1+$, but the fee for ${\mathrm{I}}^{-}$is $1$. Two ${\mathrm{Cs}}^{+}$ions and three ${\mathrm{I}}^{-}$ions $(1+)+(1-)=0$ions are used to balance the charge ((1+)+(1-)=0$. Write the positive ion first, then the negative ion in the ionic formula. The compound's correct ionic formula is$Csl$