Question

Use the periodic table to arrange the following atoms in order of increasing electronegativity: ($6.7$)

a. data-custom-editor="chemistry" $\mathrm{Cl},\mathrm{Br},\mathrm{Se}$

b.data-custom-editor="chemistry" $\mathrm{Na},\mathrm{Cs},\mathrm{O},\mathrm{S}$

c.data-custom-editor="chemistry" $\mathrm{O},\mathrm{F},\mathrm{B},\mathrm{Li}$

Short answer

(a) The increasing order of electronegativity is$\mathrm{Se}<\mathrm{Br}<\mathrm{Cl}$

(b) The increasing order of electronegativity is$\mathrm{Cs}<\mathrm{Na}<\mathrm{S}<\mathrm{O}$

(c) The increasing order of electronegativity is$\mathrm{Li}<\mathrm{B}<\mathrm{O}<\mathrm{F}$

Step-by-step solution

Part (a) Step 1: Given information

We need to find the increasing order of electronegativity

Part (a) Step 2: Explanation

We know that

Electronegativity increases as we go top-right

Therefore, increasing order of electronegativity is,

$\mathrm{Se}<\mathrm{Br}<\mathrm{Cl}$

Part (b) Step 1: Given information

We need to find increasing order of electronegativity

Part (b) Step 2: Explanation

We know that

Electronegativity increases as we go top-right

Therefore, increasing order of electronegativity is,

$\mathrm{Cs}<\mathrm{Na}<\mathrm{S}<\mathrm{O}$

Part (c) Step 1: Given information

We need to find the increasing order of electronegativity

Part (c) Step 2: Explanation

We know that,

$\mathrm{O},\mathrm{F},\mathrm{B},\mathrm{Li}$all lie in same period and different group

And electronegativity increases as we move left to right in a period

Therefore, increasing order of electronegativity is,

$\mathrm{Li}<\mathrm{B}<\mathrm{O}<\mathrm{F}$