Question

One of the ions of tin is tin(IV).

a. What is the symbol for this ion?

b. How many protons and electrons are in the ion?

c. What is the formula of tin(IV) oxide?

d. What is the formula of tin(IV} phosphate?

Short answer

a. Symbol of tin(IV) is $S{n}^{4+}$.

b. It has $50$and $46$protons and electrons respectively.

c. Formula of tin(IV) oxide is $Sn{O}_2$.

d. Formula of tin(IV) phosphate is$S{n}_3{\left(P{O}_4\right)}_4$.

Step-by-step solution

Part(a) Step 1: Given information

We need to find the symbol for tin(IV).

Part(a) Step 2: Explanation

Symbol for tin(IV) is$S{n}^{4+}$.

Part(b) Step 1: Given information

We need to find number of electrons and protons for tin(IV).

Part(b) Step 2: Explanation

Atomic number of tin(IV) is $50$so,

The number of protons are $50$.

The number of electrons are$46$due to$+4$oxidation state.

Part(c) Step 1: Given information

We need to find the formula for tin(IV) oxide.

Part(c) Step 2: Explanation

Tin(IV) oxide is also known as stannic oxide and it's formula is$Sn{O}_2$.

Part(d) Step 1: Given information

We need to find the formula for tin(IV) phosphate.

Part(d) Step 2: Explanation

Tin(IV) phosphate is also known as tin phosphate and it's formula is$S{n}_3{{\left(P{O}_4\right)}_{}}_4$.