Question

Give the IUPAC name for each of the following :

Short answer

a. The IUPAC name of the compound is $Butene$.

b. The IUPAC name of the compound is $6-methylhept-2-yne$.

c. The IUPAC name of the compound is$cyclopentene.$

d. The IUPAC name of the compound is $2-pentene$.

Step-by-step solution

Part (a) Step 1 : Given information

We have to write the IUPAC name of the given compound i.e.

Part (a) Step 2 : Simplification

We know that

• The parent chain of the given compound is of four carbon so its word root is$but.$
• It also contains an unsaturated double bond so its primary suffix is$ene.$

Hence IUPAC's name is $Butene$.

Part (b) Step 1 : Given information

We have to write the IUPAC name of the given compound i.e.

Part (b) Step 2 : Simplification

We know that

• The parent chain of the given compound is of seven carbon so it's word root is $Hept.$
• It also contains an unsaturated triple bond between the second and third carbon of the parent chain, so its primary suffix is $-yne.$
• It also contain a carbon as side chain at the sixth carbon of the parent chain.

Hence its IUPAC name is $6-methylhept-2-yne.$

Part (c) Step 1 : Given information

We have to write the IUPAC name of the given compound i.e.

Part (c) Step 2 : Simplification

We know that

• The parent chain of the given compound is of five carbons in cyclic form so its infix is $cyclo$and contains word root is$pent.$
• It also contains an unsaturated double bond so its primary suffix is $-ene.$

Hence its IUPAC name is $cyclobutene.$

Part (d) Step 1 : Given information

We have to write the IUPAC name of the given compound i.e.

Part (d) Step 2 : Simplification

We know that

• The parent chain of the given compound is of five carbons so its word root is $pent.$
• It also contains an unsaturated double bond between the second and third carbon of the parent chain so its primary suffix is $-ene.$

Hence its IUPAC name is $2-pentene.$