Question

Solve each of the following for z: $(1.4)$

a. $3z-\left(-6\right)=12$

b.$\frac{4z}{-12}=-8$

Short answer

a. The value of$z$is$2$.

b. The value of$z$is$24$.

Step-by-step solution

Part (a) step 1: Given Information

We need to find the value of $z$from equation$3z-\left(-6\right)=12$.

Part (a) step 2: Calculation

Consider:

$3z-\left(-6\right)=12$

Now, finding the value of $z$:

$$\begin{gathered} 3z-\left(-6\right)=12 \\ 3z+6=12 \\ 3z=12-6 \\ 3z=6 \\ z=\frac{6}{3} \\ z=2 \end{gathered}$$

Part (b) step 1: Given Information

We need to find the value of$z$from equation$\frac{4z}{-12}=-8$.

Part (b) step 2: Calculation

Finding the value of $z$:

so,

$$\begin{gathered} \frac{4z}{-12}=-8 \\ 4z=\left(-8\right)\times \left(-12\right) \\ 4z=96 \\ z=\frac{96}{4} \\ z=24 \end{gathered}$$