Question

On the first chemistry test, $12$students got As, $18$students got Bs, and $20$students got Cs. $\left(1.4\right)$

a. What is the percentage of students who received Bs?

Express your answer to the ones place.

b. What is the percentage of students who received Cs?

Express your answer to the ones place.

Short answer

a. The percentage of students who received Bs is $36\%$.

b. The percentage of students who received Cs is$40\%$.

Step-by-step solution

Part (a) Step 1: Given Information

We need to find the percentage of students who received Bs.

Part (a) Step 2: Explanation

Solving the percentage of Bs

Firstly, calculating the total number of students $=12+18+20$

$=50$.

Now, calculating the percentage of Bs $=\left(numberofBs\right)\left(totalnumberofstudents\right)\times 100$

$$\begin{gathered} =\left(\frac{18}{50}\right)\times 100=0.36\times 100 \\ =36\% \end{gathered}$$

Part (b) Step 1: Given Information

We need to find the percentage of students who received Cs.

Part (b) Step 2: Explanation

Solving the percentage of Cs

Firstly, calculating the total number of students $=12+18+20$

$=50$

Now, calculating the percentage of Cs $=\left(numberofCs\right)\left(totalnumberofstudents\right)\times 100$

$$\begin{gathered} =\left(\frac{20}{50}\right)\times 100=\left(0.4\right)\times 100 \\ =40\% \end{gathered}$$