Question

Evaluate each of the following:$\left(1.4\right)$

a.$-95-\left(-11\right)=\_\_\_$.

b.$\frac{152}{-19}=\_\_\_$.

c.$4-56=\_\_\_$.

Short answer

a. The answer is$-95-\left(-11\right)=-84$.

b. The answer is $\frac{152}{-19}=-8$.

c. The answer is $4-56=-52$.

Step-by-step solution

Part (a) step 1: Given Information

We need to evaluate$-95-\left(-11\right)=\_\_\_$.

Part (a) step 2: Calculation

Now,

subtraction of two negative numbers.

$$\begin{gathered} =-95-\left(-11\right) \\ =-95+11 \\ =-84 \end{gathered}$$

Part (b) step 1: Given Information

We need to evaluate$\frac{152}{-19}=\_\_\_$.

Part (b) step 2: Calculation

Here, $152$divided by $-19$.

when one positive number is divided by any negative number so the result comes in a negative sign.

$$\begin{gathered} =\frac{152}{-19} \\ =-8 \end{gathered}$$

Part (c) step 1: Given Information

We need to evaluate$4-56=\_\_\_$.

Part (c) step 2: Calculation

Here,

$$\begin{gathered} =4-56 \\ =4+\left(-56\right) \\ =-52 \end{gathered}$$