Question

a. Write an equality and two conversion factors for one tablet of the iron supplement.

b. How many grams of iron will Greg consume in one week?

Each tablet contains 65 mg of iron, which is given for iron supplementation.

Short answer

a. $1\mathrm{tablet}=65\mathrm{mg}\mathrm{of}\mathrm{iron}$

b. The mass of iron is 0.910 g.

Step-by-step solution

Part (a) Given Information

To write the unit conversion method.

part (a) Explanation

The unit conversion method that is used for converting one tablet of iron supplement is:

$$\begin{gathered} 1\mathrm{tablet}=65\mathrm{mg}\mathrm{of}\mathrm{iron} \\ \mathrm{Unit}\mathrm{conversion}: \\ \frac{1\mathrm{tablet}}{65\mathrm{mg}\mathrm{of}\mathrm{iron}}\mathrm{and}\frac{65\mathrm{mg}\mathrm{of}\mathrm{iron}}{1\mathrm{tablet}} \end{gathered}$$

Part (a) Given Information

Each tablet contains 65 mg of iron.

Part (b) Explanation

The doctor has prescribed taking the iron supplement twice daily.

$1\mathrm{tablet}=65\mathrm{mg}\mathrm{of}\mathrm{iron}\mathrm{supplement}$

So, in 2 tablets it will be:

$2\mathrm{tablets}=2\times 65\mathrm{mg}=130\mathrm{mg}$

It is asked to calculate the grams of iron taken in a week.

If a person is taking two tablets daily for one week, then the mass of iron will be:

$$\begin{gathered} \mathrm{Mass}\mathrm{of}\mathrm{iron}=7\times 130\mathrm{mg}=910\mathrm{mg} \\ 1\mathrm{g}=1000\mathrm{mg} \\ \mathrm{or} \\ 1\mathrm{mg}=\frac{1}{1000}\mathrm{g}=0.001\mathrm{g} \\ \mathrm{So}, \\ 910\mathrm{mg}=\frac{910}{1000}=0.910\mathrm{g} \end{gathered}$$

Thus, the mass of iron is 0.910 g.