Question

Calculate each of the following quantities in $0.185$moles of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$:

1. moles of$\mathrm{C}$
   
2. moles of$\mathrm{O}$
   
3. atoms of $\mathrm{H}$
4. atoms of $\mathrm{C}$

Short answer

Quantities present in $0.185$moles of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$are:

1. $1.11$moles of carbon
2. $0.185$moles of oxygen
3. $4.4\times {10}^{22}$atoms of hydrogen
4. $6.68\times {10}^{23}$atoms of carbon

Step-by-step solution

Part (a) Step 1: Given Information

We need to find number of moles of $\mathrm{C}$in $0.185$moles of${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$

Part(a) Step 2: Explanation

One mole of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$contains $6$moles of $\mathrm{C}$

So, moles of $\mathrm{C}$in $0.185$moles of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$= $6\times 0.185=1.11$

Hence, $1.11$ moles of carbon present in $0.185$ moles of${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$

Part (b) Step 1: Given Information

We need to find number of moles of $\mathrm{O}$in $0.185$moles of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$

Part(b) Step 2: Explanation

One mole of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$contains one mole of oxygen

So, moles of oxygen in $0.185$moles of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$= $0.185\times 1=0.185$

Hence,$0.185$ moles of oxygen is present in $0.185$moles of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$.

Part (c) Step 1: Given Information

We need to find number of atoms of $\mathrm{H}$in $0.185$moles of${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$

Part(c) Step 2: Explanation

One mole of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$contains $14$mole of $\mathrm{H}$in it.

Number of atoms of $\mathrm{H}$in $0.185$moles of${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$ =$0.185\times 4\times 6.02\times {10}^{23}=4.4\times {10}^{22}$

Hence, $4.4\times {10}^{22}$atoms are present.

Part (d) Step 1: Given Information

We need to find number of atoms of $\mathrm{C}$in $0.185$moles of${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$

Part(d) Step 2: Explanation

One mole of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$ contains $6$mole of $\mathrm{C}$in it.

Number of atoms of $\mathrm{C}$in $0.185$moles of data-custom-editor="chemistry" ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$= $$\begin{gathered} 0.185\times 6\times 6.02\times {10}^{23} \\ =6.68\times {10}^{23} \end{gathered}$$

Hence, $6.68\times {10}^{23}$ atoms are present.