Question

Write all of the mole-mole factors for each of the following chemical equations:

a.$2S{O}_2\left(g\right)+O_2\left(g\right)\to 2S{O}_3\left(g\right)$

b.data-custom-editor="chemistry" $4P\left(s\right)+5{\mathrm{O}}_2\left(g\right)\to 2P_{\mathit{2}}{O}_{\mathit{5}}\left(s\right)$

Short answer

(a) The mole-mole factors are$\frac{2\mathrm{mole}{\mathrm{SO}}_2}{1\mathrm{mole}{\mathrm{O}}_2},\frac{1mole{O}_2}{2moleS{O}_3}and\frac{2moleS{O}_3}{2moleS{O}_2}$.

(b) The mole-mole factors are$\frac{4\mathrm{mole}\mathrm{P}}{5\mathrm{mole}{\mathrm{O}}_2},\frac{5mole{O}_2}{2mole{P}_2{O}_5}and\frac{2mole{P}_2{O}_5}{4moleP}$.

Step-by-step solution

Part (a) Step 1: Given Information

We are given the equation and we have to find the mole-mole factors.

Part (a) Step 2: Explanation

In the given equation, there are ways to find mole factors by considering two compounds every time.

consider,${\mathrm{SO}}_2\mathrm{and}{\mathrm{O}}_2$

$2$mole ${\mathrm{SO}}_2=$$1$mole ${\mathrm{O}}_2$

which gives the $\frac{2moleS{O}_2}{1mole{O}_2}$mole-mole factor.

Now consider $O_{2}andS{O}_3$

$1$mole role="math" localid="1652676267214" ${\mathrm{O}}_2=2$mole ${\mathrm{SO}}_3$

which gives the$\frac{1mole{O}_2}{2moleS{O}_3}$mole-mole factor.

Again, consider $S{O}_{2}andS{O}_3$

$2$mole $S{O}_2=2$mole $S{O}_3$

which gives the $\frac{2moleS{O}_3}{2moleS{O}_2}$mole-mole factor.

Hence, these are the mole-mole factors.

Part (b) Step 1: Given Information

We are given the equation and we have to find the mole-mole factors.

Part (b) Step 2: Explanation

In the given equation, there are ways to find mole factors by considering two compounds every time.

Consider P and ${\mathrm{O}}_2$

$4$mole P=$5$mole ${\mathrm{O}}_2$

which gives the$\frac{4\mathrm{mole}\mathrm{P}}{5\mathrm{mole}{\mathrm{O}}_2}$mole-mole factor.

Now consider,${\mathrm{O}}_2\mathrm{and}{\mathrm{P}}_2{\mathrm{O}}_5$

$5$mole$O_2=2$mole ${\mathrm{P}}_2{\mathrm{O}}_5$

which gives the$\frac{5mole{O}_2}{2mole{P}_2{O}_5}$ mole-mole factor.

Again, consider $Pand{P}_2{O}_5$

$4$mole P=$2$moledata-custom-editor="chemistry" ${\mathrm{P}}_2{\mathrm{O}}_5$

which gives the data-custom-editor="chemistry" $\frac{2\mathrm{mole}{\mathrm{P}}_2{\mathrm{O}}_5}{4\mathrm{mole}\mathrm{P}}$mole-mole factor.

Hence, these are the mole-mole factors.