Question

Dinitrogen oxide (or nitrous oxide), ${\mathrm{N}}_2\mathrm{O}$, also known as laughing gas, is widely used as an anesthetic in dentistry.

a. How many grams are in localid="1653463981976">1.50molesof dinitrogen oxide?

b. How many moles are in localid="1653463992855" $34.0$gof dinitrogen oxide?

Short answer

(a) The $66$g is in $1.50$moleof dinitrogen oxide

(b) The $0.772$moleare in $34$gof dinitrogen oxide

Step-by-step solution

Part (a) Step 1: Given information  

We need to find the mass in $1.50$moleof dinitrogen oxide

Part (a) Step 2: Simplify 

We know that

A mole is equal to molar mass

And molar mass of dinitrogen oxide is,$44\mathrm{g}/\mathrm{mol}$

Therefore, the mass in $1.50$moleof dinitrogen oxide is,$44\frac{\mathrm{g}}{\cancel{\mathrm{mol}}}\times 1.5\cancel{\mathrm{mol}}=66\mathrm{g}$

Part (b) Step 1: Given information   

We need to find the no. of moles in $34$gof dinitrogen oxide

Part (b) Step 2: Simplify 

We know that

A mole is equal to molar mass

And molar mass of dinitrogen oxide is, $44\mathrm{g}/\mathrm{mol}$

Therefore, the no. of moles in $34$gof dinitrogen oxide is,$\frac{34\cancel{\mathrm{g}}}{44{\displaystyle \raisebox{1ex}{$\cancel{\mathrm{g}}$}\!\left/ \!\raisebox{-1ex}{$\mathrm{mol}$}\right.}}=0.772\mathrm{mol}$