Question

a. Cyclopropane, ${\mathrm{C}}_3{\mathrm{H}}_6$, is an anesthetic given by inhalation. How many grams are in localid="1653462251487" $0.25$moleof cyclopropane?

b. The sedative Demerol hydrochloride has the formula $C_{15}{H}_{22}CIN{O}_2$. How many grams are in localid="1653462261430" $0.025$moleof Demerol hydrochloride?

Short answer

(a) The $10.5$gare in $0.25$moleof cyclopropane

(b) The $5.86$gare in $0.025$moleof Demerol hydrochloride

Step-by-step solution

Part (a) Step 1: Given information 

We need to find the mass in $0.25$mole of cyclopropane

Part (a) Step 2: Simplify

We know that

A mole is equal to molar mass

And molar mass of cyclopropane is, $42\mathrm{g}/\mathrm{mol}$

Therefore, the mass in $0.25$moleof cyclopropane is,$42\frac{\mathrm{g}}{\cancel{\mathrm{mol}}}\times 0.25\cancel{\mathrm{mol}}=10.5\mathrm{g}$

Part (b) Step 1: Given information  

We need to find the mass in $0.025$moleof Demerol hydrochloride

Part (b) Step 2: Simplify 

We know that

A mole is equal to molar mass

And molar mass of Demerol hydrochloride is, $234.3\mathrm{g}/\mathrm{mol}$

Therefore, the mass in $0.025$moleof Demerol hydrochloride is,$234.3\frac{\mathrm{g}}{\cancel{\mathrm{mol}}}\times 0.025\cancel{\mathrm{mol}}=5.86\mathrm{g}$