Question

Calculate the mass, in grams, for each of the following:

a.$1.50$moles of $Na$

b. $2.80$ moles of $Ca$

c.$0.125$ mole of$C{O}_2$

d. $0.0485$mole of $N{a}_{2}C{O}_3$

e. $7.14x{10}^2$moles of $PC{I}_3$

Short answer

The mass in gram for each of following is :

a. $1.50$moles of $Na$is $34.5$g

b. $2.80$moles of $Ca$is$117$g

c. $0.125$mole of $C{O}_2$is localid="1653460284777" $5.50$g

d. $0.0485$mole of $N{a}_{2}C{O}_3$ is localid="1653460294192" $5.141$g

e. $7.14\times {10}^2$moles of $PC{l}_3$is$98053.6$g

Step-by-step solution

Part (a) Step 1: Given information

We have to find that how much is the the mass in grams for$1.50$moles of $Na$

Part (a) Step 2: Explanation

Here $1$mole is atomic mass of substance expressed in grams .

mass of $1$mole is localid="1653460370376" $22.9$g

Therefore mass of $1.5$mole = localid="1653461513655" role="math" $1.5\cancel{moles}\times 22.9\frac{g}{\cancel{moles}}=34.5$g

Part (b) Step 1: Given information

We have to find that how much is the the mass in grams for $2.80$ moles of $Ca$

Part (b) Step 2: Explanation

Here $1$mole is atomic mass of substance expressed in grams .

mass of $1$mole is localid="1653460434870" $40.078$g

Therefore mass of $2.8$moles is localid="1653461624821" role="math" $2.80\cancel{moles}\times 40.078\frac{g}{\cancel{moles}}=117$g

Part (c) Step 1: Given information

We have to find that how much is the the mass in grams for $0.125$mole of$C{O}_2$

Part (c) Step 2: Explanation

Here $1$mole is atomic mass of substance expressed in grams .

mass of $1$mole is localid="1653460485779" $44.01$u

Therefore mass of $0.125$moles is localid="1653461688666" role="math" $44.01\frac{g}{\cancel{moles}}\times 0.125\cancel{moles}=5.50$g

Part (d) Step 1: Given information

We have to find that how much is the the mass in grams for $0.0485$mole of$N{a}_{2}C{O}_3$

Part (d) Step 2: Explanation

Here $1$mole is atomic mass of substance expressed in grams .

mass of $1$mole is localid="1653460510915" $106$g/moles

therefore mass of $0.0485$moles is localid="1653461720992" role="math" $106\frac{g}{\cancel{moles}}\times 0.0485\cancel{moles}=5.141$g

Part (e) Step 1: Given information

We have to find that how much is the the mass in grams for $7.14\times {10}^2$moles of $PC{l}_3$

Part (e) Step 2: Explanation

Here $1$mole is atomic mass of substance expressed in grams .

mass of $1$mole is localid="1653460555113" $137.33$g/mol

137.33Therefore mass of $7.14\times {10}^2$moles is localid="1653461763907" role="math" $7.14\times 10\cancel{{}^{2}moles}\times 137.33\frac{g}{\cancel{moles}}=98053.62$g