Question

Calculate the molar mass for each of the following:

a. ${\mathrm{FeSO}}_4$, iron supplement

b. ${\mathrm{Al}}_2{\mathrm{O}}_3$, absorbent and abrasive

c. ${\mathrm{C}}_7{\mathrm{H}}_5{\mathrm{NO}}_3\mathrm{S}$, saccharin, artificial sweetener

Short answer

a. The molar mass of ${\mathrm{FeSO}}_4$is$151.86\mathrm{g}$

b. The molar mass of ${\mathrm{Al}}_2{\mathrm{O}}_3$is$101.93\mathrm{g}$$101.93g$

c. The molar mass of localid="1652527513872" ${\mathrm{C}}_7{\mathrm{H}}_5{\mathrm{NO}}_3\mathrm{S}$islocalid="1653486642269" $183.10\mathrm{g}$

Step-by-step solution

Part (a) Step 1 : Given information

We have to find the molar mass of${\mathrm{FeSO}}_4$

Part (a) Step 2 : Simplification

We know that,

Molar mass of one $\mathrm{Fe}$atom =localid="1653486686471" $55.84\mathrm{g}$

Molar mass of one $\mathrm{S}$atom =localid="1653486674220" $32.06\mathrm{g}$

Molar mass of one $\mathrm{O}$atom =localid="1653486665860" $15.99\mathrm{g}$

So, the molar mass of${\mathrm{FeSO}}_4$=$55.84+32.06+4\left(15.99\right)$=localid="1653486655433" $151.86\mathrm{g}$

Part (b) Step 1 : Given information

We have to find the molar mass of${\mathrm{Al}}_2{\mathrm{O}}_3$

Part (b) Step 2 : Simplification

We know that,

Molar mass of one $\mathrm{Al}$atom =localid="1653486708328" $26.98\mathrm{g}$

Molar mass of one $\mathrm{O}$atom =localid="1653486699563" $15.99\mathrm{g}$

So, the molar mass of${\mathrm{Al}}_2{\mathrm{O}}_3$=$2\left(26.98\right)+3\left(15.99\right)$=localid="1653486717737" $101.93\mathrm{g}$

Part (c) Step 1 : Given information

We have to find the molar mass of${\mathrm{C}}_7{\mathrm{H}}_5{\mathrm{NO}}_3\mathrm{S}$

Part (c) Step 2 : Simplification

We know that,

Molar mass of one $\mathrm{C}$atom = localid="1653486731025" $12.01\mathrm{g}$

Molar mass of one $\mathrm{H}$atom =localid="1653486740897" $1.00\mathrm{g}$

Molar mass of one $\mathrm{N}$atom =localid="1653486749631" $14.00\mathrm{g}$

Molar mass of one $\mathrm{O}$atom =localid="1653486757920" $15.99\mathrm{g}$

Molar mass of one $\mathrm{S}$atom =localid="1653486767035" $32.06\mathrm{g}$

So, the molar mass of${\mathrm{C}}_7{\mathrm{H}}_5{\mathrm{NO}}_3\mathrm{S}$=$7\left(12.01\right)+5\left(1.00\right)+14.00+3\left(15.99\right)+32.06$=localid="1653486777161" $183.10\mathrm{g}$