Question

Benadryl is an over-the-counter drug used to treat allergy symptoms. The formula of Benadryl is${\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO}$.
a. How many moles of $\mathrm{C}$are present in$0.733$ mole of Benadryl?
b. How many moles of $\mathrm{H}$are present in$2.20$ moles of Benadryl?
c. How many moles of $\mathrm{N}$ are present in $1.54$ moles of Benadryl?

Short answer

Our required answers are:

1. $12.461$moles of data-custom-editor="chemistry" $\mathrm{C}$present in$0.733$moles Benadryl .
2. $46.20$moles of data-custom-editor="chemistry" $\mathrm{H}$present in $2.20$moles Benadryl.
3. $1.54$ moles of data-custom-editor="chemistry" $\mathrm{N}$ are present in $1.54$ moles of Benadryl.

Step-by-step solution

Part(a) Step 1: Given Information

We need to find moles of $\mathrm{C}$in $0.733$moles of Benadryl .

Part(a) Step 2: Explanation

Using equalities and conversion factor using subscripts:

One mole of ${\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO}$= $17$moles of $\mathrm{C}$

Conversion Factor= $\frac{17mole\mathrm{C}}{1\mathrm{mole}{\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO}}$

Moles of in moles of naproxen = role="math" localid="1652761565450" $$\begin{gathered} \frac{17mole\mathrm{C}}{1\mathrm{mole}{\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO}}\times 0.733\mathrm{mole}{\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO} \\ =12.461\mathrm{mole}\mathrm{C} \end{gathered}$$

Hence, $12.461$moles of present in $0.733$moles Benadryl .

Part(b) Step 1: Given Information

We need to find moles of $\mathrm{H}$in $2.20$moles of Benadryl .

Part(b) Step 2: Explanation

Using equalities and conversion factor using subscripts:

One mole of ${\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO}$= $21$ moles of$\mathrm{H}$

Conversion Factor=$\frac{21mole\mathrm{H}}{1mole{\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO}}$

Moles of in moles of naproxen =$$\begin{gathered} \frac{21mole\mathrm{H}}{1mole{\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO}}\times 2.20mole{\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO} \\ =46.20mole\mathrm{H} \end{gathered}$$

Hence, $46.20$moles of $\mathrm{H}$present in $2.20$moles Benadryl .

Part(c) Step 1: Given Information

We need to find moles of $\mathrm{N}$in $1.54$moles of Benadryl .

Part(c) Step 2: Explanation

Using equalities and conversion factor using subscripts:

One mole of ${\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO}$= $1$ moles of$\mathrm{N}$

Conversion Factor=$\frac{1mole\mathrm{N}}{1mole{\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO}}$

Moles of in moles of naproxen =$$\begin{gathered} \frac{1mole\mathrm{N}}{1mole{\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO}}\times 1.54mole{\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO} \\ =1.54mole\mathrm{N} \end{gathered}$$

Hence, $1.54$moles of $\mathrm{N}$present in $1.54$moles Benadryl .