Question

Draw the line-angle formula and write the IUPAC name for each of the following: (14.1)

a. A carboxylic acid that has the formula ${\mathrm{C}}_3{\mathrm{H}}_{40}{\mathrm{O}}_2$, with no substituents

b. A carboxylic acid that has the formula ${\mathrm{C}}_3{\mathrm{H}}_{10}{\mathrm{O}}_2$, with two methyl substituents

Short answer

Part (a) The formula for a carboxylic acid's line-angle formula${\mathrm{C}}_5{\mathrm{H}}_{10}{\mathrm{O}}_2$is

Pentatonic acid is the IUPAC name for this compound because it contains 5 carbon atoms.

Part(b)A carboxylic acid's line-angle formula${\mathrm{C}}_5{\mathrm{H}}_{10}{\mathrm{O}}_2$, is

The compound's IUPAC name is 2,3-dimethyl propanoic acid..

Step-by-step solution

Given data

Find the line-angle formula for each of the following and write the IUPAC name.

Introduction

Carboxylic acids are weak acids that produce hydronium ions and neutralize bases in water. The carbon atom of a carbonyl group is attached to a hydroxyl group to form a carboxyl group in carboxylic acids.

The carboxyl functional group can be attached to either an alkyl or an aromatic group..

Part (a) Step 3: The line-angle formula of a carboxylic acid is the formula 

a) A carboxylic acid's line-angle formula is formula${\mathrm{C}}_5{\mathrm{H}}_{10}{\mathrm{O}}_2$is

Pentatonic acid is the IUPAC name for this compound because it contains 5 carbon atoms.

Part (b) Step 4: The formula for a carboxylic acid's line-angle formula 

b) The formula for a carboxylic acid's line-angle formula ${\mathrm{C}}_5{\mathrm{H}}_{10}{\mathrm{O}}_2$, with two methyl substitutes is

Because the compound contains three carbon atoms and two methyl groups at $2^{\text{nd}}$and $3^{\text{rd}}$The compound's IUPAC name is 2,3-dimethyl propanoic acid.