Question

Write the balanced chemical equation for the reaction of each of the following carboxylic acids with NaOH:

a. formic acid

b. 3-chloropropanoic acid

c. benzoic acid

Short answer

(part a)

(part b)

(part c)

Step-by-step solution

Introduction (part a)

An oxygen molecule is really a harmonious ratio expression whereby the charge and the group of particles to every constituent there in event are the same between the reactants and the products. In these other respects, its mass and voltage from both sides of both the response is comparable.

Given Information (part a)

Formic acid seems to be the carboxylic acid in consideration. The hereunder is the formula of formic acid:

Explanation (part a) 

(part a) Sodium molar ratio with liquid are created while formic acid combines with hydrochloric acid. So here is the stoichiometric ratio for all of this neutral public response:

Given Information (part b) 

$3$-chloropropanoic acid is really the carboxylic acid in consideration. The trying to follow is the formula of $3$-chloropropanoic acid:

Explanation (part b)

(part b) The $3$-chloropropanoic acid mixes with hydrochloric acid to create sodium $3$-chloropropanoate (NaOH) . As both an outcome, such neutralize reaction's equilibrium equation is given:

Given Information (part c)

A carboxyl group is bonded to a benzene ring there in specified carboxylic acid, which itself is benzoic acid. The follows seems to be the formula of benzoic acid:

Explanation (part c) 

(part c) Benzoic acid yields sodium benzoate once it mixes using $NaOH$. As a conclusion, that equalization reaction's structural formula is: