Question

Which compound in each pair would be more soluble in water? Explain. ($12.2$)

a. $bu\tan e$or$1-propanol$

b.$2-propanol$or$diethylether$

c. $ethanol$or$1-hexanol$

Short answer

(a) The $1-propanol$will be more soluble in water

(b) The $2-propanol$will be more soluble in water

(c) The$ethanol$will be more soluble in water

Step-by-step solution

Part (a) Step 1: Given information

We need to find that which out of the $bu\tan e$and$1-propanol$will be more soluble in water

Part (a) Step 2: Explanation

We know that

The compound which will form more hydrogen bonds will be more soluble in water.

And out of the given compounds $1-propanol$will form hydrogen bonds

Therefore, The $1-propanol$will be more soluble in water

Part (b) Step 1: Given information 

We need to find that which out of the $2-propanol$and $diethylether$will be more soluble in water

Part (b) Step 2: Explanation 

We know that

The compound which will form more hydrogen bonds will be more soluble in water.

And out of the given compounds $2-propanol$will form hydrogen bonds

Therefore, The $2-propanol$will be more soluble in water

Part (c) Step 1: Given information 

We need to find that which out of the $ethanol$and $1-hexanol$ will be more soluble in water

Part (c) Step 2: Explanation 

We know that

The compound which will form more hydrogen bonds will be more soluble in water.

And out of the given compounds $ethanol$will form hydrogen bonds

Therefore, The $ethanol$will be more soluble in water