Question

Give IUPAC name for each of the following.

Short answer

(a) IUPAC name is Propenal .

(b) IUPAC name is $2methylpent3-one$.

(c) IUPAC name is $3,4dimethylcyclohexenone$.

(d) IUPAC name is localid="1652762698568" $2bromobenzaldehyde$.

Step-by-step solution

Part (a) Step 1: Given Information

We need to find the IUPAC name of the compound.

Part (a) Step 2: Explanation

We are given a compound in which $-CHO$group is present and we know that it is higher Preference group that's why counting start from this group side .

Therefore, IUPAC name is $propanal$.

Part (b) Step 1: Given Information

We need to find the IUPAC name of the compound.

Part (b) Step 2: Explanation

We are given a compound in which $C=O$group is present . then we should take a long chain and Ensure that $-CHO$group is near. that's why counting will start from right part Therefore , the IUPAC name is $2methylpent-3-one$

Part (c) Step 1: Given Information

We need to find the IUPAC name of the compound.

Part (c) Step 2: Explanation

We are given a compound in which $C=O$group is present and we know that it is higher preference than other groups that's why counting is start from this group carbon that's why the IUPAC name is $3,4dimethylcyclohexenon$.

Part (d) Step 1: Given Information

We need to find the IUPAC name of the compound.

Part (d) Step 2: Explanation

We are given a compound in which $-CHO$group is present and that group is higher preference in this compound and counting will start from this. that's why the IUPAC name is $2Bromobenzaldehyde.$