Question

Complete the following table-

Short answer

$H_{2}O$conjugate base- $O{H}^{-}$

$C{N}^{-}$acid- HCN

$HN{O}_2$conjugate base- role="math" localid="1653111199726" $N{O_2}^{-}$

${\mathrm{H}}_2{\mathrm{PO}}_4^{-}$acid-$H_{3}P{O}_4$

Step-by-step solution

Given Information

A form acid-base pair consists of two substances that are exclusively different due to the presence of a proton (H⁺). A form acid is framed when a proton is added to a base, and a form base is shaped when a proton is eliminated from an acid.

Explanation

Acid$H_{2}O$- when one $H^{+}$is removed the conjugate base is formed which is $O{H}^{-}$

Conjugate base$C{N}^{-}$- When one $H^{+}$is added the acid is formed which is HCN.

Acid$HN{O}_3$- when one $H^{+}$is removed the conjugate base is formed which $N{O_2}^{-}$

Conjugate base${\mathrm{H}}_2{\mathrm{PO}}_4^{-}$- When one$H^{+}$ is added the acid is formed which is$H_{3}P{O}_4$