Question

Write the balanced chemical equation for the neutralization reaction of stomach acid HCL with $CaC{O}_3$an ingredient in some antacids.

Short answer

$2\mathrm{HCl}\left(aq\right)+{\mathrm{CaCO}}_3\left(s\right)\to {\mathrm{CaCl}}_2\left(aq\right)+{\mathrm{CO}}_2\left(g\right)+{\mathrm{H}}_2\mathrm{O}\left(l\right)$

Step-by-step solution

Given Information

Write the balanced chemical equation for the neutralization reaction of stomach acid HCL with$CaC{O}_3$

Explanation

The reaction is,

$2\mathrm{HCl}\left(aq\right)+{\mathrm{CaCO}}_3\left(s\right)\to {\mathrm{CaCl}}_2\left(aq\right)+{\mathrm{CO}}_2\left(g\right)+{\mathrm{H}}_2\mathrm{O}\left(l\right)$

To neutralize the acidity in our stomach we consume antacid. One such dynamic element of the stomach settling agent is $CaC{O}_3$, which can be utilized to neutralize HCL present in the stomach. HCL is monobasic acid and $CaC{O}_3$ is a di-acidic base so two moles of HCL will be neutralized by one mole of$CaC{O}_3$.