Question

In Larry's esophageal pH test, a pH value of 3.60 was recorded in the esophagus. What is the $\left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$in his esophagus?

Short answer

The concentration of$\left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$is$2.5\times {10}^{-4}\mathrm{M}$.

Step-by-step solution

Step - 1   Introduction

The solution's $\mathrm{pH}$can be defined as the negative logarithmic (base 10) of the $\left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$concentration.

$\mathrm{pH}=-\log \left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$

$\mathrm{pOH}=-\log \left[{\mathrm{OH}}^{-}\right]$

$\mathrm{pH}+\mathrm{pOH}=14$

Step - 2  Explanation

Calculate the $\left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$concentration using the formula: the given $pH$ value is 3.60.

$pH=-\log \left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$

$3.6=-\log \left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$

$\left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]={10}^{(-3.6)}$

$\left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]=2.5\times {10}^{-4}\mathrm{M}$