Question

When food enters the stomach,$\mathrm{HCl}$ is released and the $\left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$ of the stomach fluid rises to $4\times {10}^{-2}\mathrm{M}$. What is the $\mathrm{pH}$ of the stomach fluid?

Short answer

The gastric fluid's pH text is 1.4.

Step-by-step solution

Step - 1  Given information

• The solution's $\mathrm{pH}$can be defined as the negative logarithmic (base 10) of the $\left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$ concentration.

$\mathrm{pH}=-\log \left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$

$\mathrm{pOH}=-\log \left[{\mathrm{OH}}^{-}\right]$

$\mathrm{pH}+\mathrm{pOH}=14$

 step - 2    Explanation

• The stomach fluid concentration is $2.0\times {10}^{-4}\mathrm{M}$. Use the following formula to calculate the $\mathrm{pH}$solution:

$pH=-\log \left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$

$=-\log \left[4.0\times {10}^{-2}\right]$

$=2-\log (4.0)$

$=2-0.6$0

$=1.4$

As a result, the stomach fluid's pH text is 1.4.