Question

At rest, the $\left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$of the stomach fluid is $2.0\times {10}^{-4}\mathrm{M}$. What is the$\mathrm{pH}$ of the stomach fluid?

Short answer

The pH text of the stomach fluid is 3.70.

Step-by-step solution

Step - 1   Introduction

The solution's $\mathrm{pH}$can be defined as the negative logarithmic (base 10) of the $\left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$ concentration .

$\mathrm{pH}=-\log \left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$

$\mathrm{pOH}=-\log \left[{\mathrm{OH}}^{-}\right]$

$\mathrm{pH}+\mathrm{pOH}=14$

Step - 2   Explanation

The solution has an acid concentration of $2.0\times {10}^{-4}\mathrm{M}$. Calculate the solution's $\mathrm{pH}$using the following formula:

$pH=-\log \left[{\mathrm{H}}_3{\mathrm{O}}^{*}\right]$

$=-\log \left[2.0\times {10}^{-4}\right]$

$=4-\log (2.0)$

$=3.70$

As a result, the pH text of the stomach fluid is 3.70.