Question

Complete the following table:

Short answer

i) The pH value is greater than $7.0$and is basic

ii) The ion value $\left[O{H}^{-}\right]$is determined as $3.09\times {10}^{-11}M$

iii) The pH value is lesser than$7$and is acidic

Step-by-step solution

Introduction 

The given is the table with components

The objective is to complete the table

Explanation 

(i)

$$\begin{gathered} [OH-]=1.0\times {10}^{-6}M \\ \left[H_3{O}^{+}\right]= \\ \left[H_3{O}^{+}\right]= \\ \left[H_3{O}^{+}\right]=1.0\times {10}^{-8}M \\ pH=-\log \left[H_3{O}^{+}\right] \\ pH=-\log [1.0\times {10}^{-8}]=8 \\ pH>7.0 \\ so,basic \end{gathered}$$

Explanation 

(ii)

$$\begin{gathered} pH=3.49<7.0 \\ so,Acidic \\ \left[H_3{O}^{+}\right]={10}^{-pH} \\ \left[H_3{O}^{+}\right]={10}^{-3.49}=3.236\times {10}^{-4}M \\ \left[O{H}^{-}\right]= \\ \left[O{H}^{-}\right]==3.09\times {10}^{-11}M \end{gathered}$$

Explanation 

(iii)

$$\begin{gathered} \left[H_3{O}^{+}\right]=2.8\times {10}^{-5}M \\ \left[O{H}^{-}\right]= \\ \left[O{H}^{-}\right]= \\ [OH-]=3.571\times {10}^{-10}M \\ pH=-\log \left[H_3{O}^{+}\right] \\ pH=-\log [2.8\times {10}^{-5}]=4.55 \\ pH<7.0 \\ so,Acidic \end{gathered}$$