Question

10.25 Why are the concentrations of${\mathrm{H}}_3{\mathrm{O}}^{+}$and${\mathrm{OH}}^{-}$equal in pure water?

Short answer

In pure water, $\left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]=\left[{\mathrm{OH}}^{-}\right]$because in pure water, the transfer of a proton between two water molecules produces equal numbers of $H_3{O}^{+}$and ${\mathrm{OH}}^{-}$

Step-by-step solution

Introduction

The given are the two equations $H_3{O}^{-}$ and$O{H}^{-}$ . To find how both are equal in pure water?

Explanation

In pure water, $\left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]=\left[{\mathrm{OH}}^{-}\right]$because in pure water, the transfer of a proton between two water molecules produces equal numbers of $H_3{O}^{+}$and$O{H}^{-}$