Question

Write the formula for the conjugate acid for each of the following bases:

a.${\mathrm{SO}}_4^{2-}$

b.$C{N}^{-}$

c.$N{H}_3$

d.$Cl{O}_2^{-}$

Short answer

(Part a) $$\begin{gathered} H^{+}+S{O}_4^{-2}\rightleftarrows HS{O}_4^{-} \\ \left(base\right)(conjugateacid) \end{gathered}$$

(Part b) $$\begin{gathered} H^{+}+C{N}^{-}\rightleftarrows HCN \\ \left(base\right)(conjugateacid) \end{gathered}$$

(Part c) $$\begin{gathered} H^{+}+N{H}_3\rightleftarrows N{H}_4^{+} \\ \left(base\right)(conjugateacid) \end{gathered}$$

(Part d) $$\begin{gathered} H^{+}+Cl{O}_2^{-}\rightleftarrows HCl{O}_2 \\ \left(base\right)(conjugateacid) \end{gathered}$$

Step-by-step solution

Introduction (Part a) 

The given are the bases $S{O}_4^{2-},C{N}^{-},N{H}_3,Cl{O}_2^{-}$. To find the formula for the conjugate acid for each of the given bases

explanation of (Part a)

Conjugate acid is formed from the base by a gain of $\mathrm{H}+$ion. ${\mathrm{SO}}_4^{2-}$gain one proton and form $HS{O}_4^{-}$, it is the conjugate acid for${\mathrm{SO}}_4^{2-}$

localid="1652617304806" $$\begin{gathered} H^{+}+S{O}_4^{-2}\rightleftarrows HS{O}_4^{-} \\ \left(base\right)(conjugateacid) \end{gathered}$$

explanation of (Part b)

Conjugate acid is formed from the base by a gain of $\mathrm{H}+$ion. ${\mathrm{CN}}^{-}$gain one proton and form$HCN$, it is the conjugate acid for $C{N}^{-}$.

localid="1652866897437" $$\begin{gathered} H^{+}+C{N}^{-}\rightleftarrows HCN \\ \left(base\right)(conjugateacid) \end{gathered}$$

explanation of (Part c)

Conjugate acid is formed from the base by the gain of $\mathrm{H}+$an ion. $N{H}_3$gain one proton and form $N{H}_4^{+}$, it is the conjugate acid for $N{H}_3$.

localid="1652617496596" $$\begin{gathered} H^{+}+N{H}_3\rightleftarrows N{H}_4^{+} \\ \left(base\right)(conjugateacid) \end{gathered}$$

explanation of (Part d)

Conjugate acid is formed from the base by a gain of $\mathrm{H}+\mathrm{ion}.{\mathrm{ClO}}_2^{-}$gain one proton and forms $HCl{O}_2$, it is the conjugate acid for $Cl{O}_2^{-}$.

localid="1652617564141" $$\begin{gathered} H^{+}+Cl{O}_2^{-}\rightleftarrows HCl{O}_2 \\ \left(base\right)(conjugateacid) \end{gathered}$$