Chapter 8: Problem 48
For a cell reaction involving a twoelectron change, the standard EMF of the cell is found to be \(0.295 \mathrm{~V}\) at \(25^{\circ} \mathrm{C}\). The equilibrium constant of the reaction at \(25^{\circ} \mathrm{C}\) will be (a) \(1 \times 10^{10}\) (b) \(1 \times 10^{-10}\) (c) \(29.5 \times 10^{-2}\) (d) \(2 \times 10^{10}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.