Chapter 8: Problem 19
What is the solubility product of saturated solution of \(\mathrm{Ag}_{2} \mathrm{CrO}_{4}\) in water at \(298 \mathrm{~K}\) if the EMF of the cell: Ag | Ag' (satd. \(\left.\mathrm{Ag}_{2} \mathrm{CrO}_{4}\right) \| \mathrm{Ag}^{+}(0.1 \mathrm{M}) \mid \mathrm{Ag}\) is \(0.162\) \(\mathrm{V}\) at \(298 \mathrm{~K} ?[2.303 R T / F=0.06, \log 2=0.3]\) (a) \(2.0 \times 10^{-4}\) (b) \(3.2 \times 10^{-11}\)
Short Answer
Step by step solution
Write the Nernst Equation
Calculate the Standard Cell Potential, E^0
Calculate the Concentration of Silver Ions, [Ag+]
Calculate the Solubility Product, Ksp
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Nernst Equation
In its general form, it expresses the potential of an electrochemical cell as a function of the standard cell potential (\(E^0\)) and the activities (approximately, concentrations) of the reactants and products. The equation is: \[ E = E^0 - \frac{RT}{nF} \ln(Q) \] where \(E\) is the cell potential, \(R\) is the universal gas constant, \(T\) is the temperature in kelvins, \(n\) is the number of moles of electrons transferred, \(F\) is the Faraday constant, and \(Q\) is the reaction quotient, which is the ratio of the products' concentrations to reactants' concentrations, each raised to the power of their stoichiometric coefficients. In our context, \(E = 0.162 V \), and by converting the natural logarithm to log base 10 using the provided relationship \(2.303 RT/F = 0.06 V\), the Nernst equation simplifies to a more manageable form that can be used directly for calculations.
Concentration Cell
The key thing to note for a concentration cell is that the standard cell potential (\(E^0\)) is zero because the electrode materials are identical under standard conditions. However, as we have different ion concentrations in the two half-cells, there is an electric potential difference due to this imbalance. The Nernst equation becomes particularly handy here to calculate this potential difference, as seen in our exercise.
Relevance to the Exercise
In the given problem, the presence of an EMF (\(0.162 V\)) signifies that there are different concentrations of \(Ag^+\) ions across the cell. The concentration cell concept helps us recognize that the electrical potential arises due to this concentration difference, even when the electrodes are made of the same material.Standard Cell Potential
In a concentration cell, \(E^0\) is curiously zero, as we have seen in the exercise solution, because the electrodes are the same material, canceling out any potential difference if they were at equal concentrations. This zeros out any inherent 'preference' for electron movement, and any observed potential comes purely from the concentration differences of the ions involved.
Contextual Insight
With the exercise provided, recognizing that \(E^0\) equals zero for a concentration cell is a crucial step in applying the Nernst equation to find the unknown ion concentrations, which then allows us to decipher the solubility product for \(Ag_2CrO_4\).Physical Chemistry Competitive Examinations
When you delve into physical chemistry, you will frequently navigate through calculations involving the interplay of various electrochemical concepts, just like our problem involving the solubility product of \(Ag_2CrO_4\). Being comfortable with these concepts can make a substantial difference in your performance in these competitive settings. It is advisable to practice these kinds of problems, understand the theoretical underpinnings, and learn the shortcuts and approximations that can save time during the exam.