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To a solution of acetic acid, solid sodium acetate is gradually added. When ' \(\mathrm{x} \mathrm{g}\) ' of the salt has been added, the \(\mathrm{pH}\) has a certain value. When total 'y g' of the salt has been added, the \(\mathrm{pH}\) has been further raised by \(0.6\) units. What is the ratio of \(x: y ?(\log 3.98=0.6)\) (a) \(3.98: 1\) (b) \(1: 3.98\) (c) \(2: 3.98\) (d) \(3.98: 2\)

Short Answer

Expert verified
The ratio of x to y is (a) 3.98:1.

Step by step solution

01

Understand the Buffer System

Recognize that the solution of acetic acid and sodium acetate forms a buffer system. The pH change suggests that the acid-base equilibrium is being modified by the addition of the salt (sodium acetate).
02

Apply the Henderson-Hasselbalch Equation

Use the Henderson-Hasselbalch equation for buffer solutions: \[ pH = pKa + \log\left(\frac{[\text{A}^{-}]}{[\text{HA}]}, \right) \] where \( [\text{A}^{-}] \) is the concentration of acetate ion and \( [\text{HA}] \) is the concentration of acetic acid.
03

Calculate the Ratio from pH Change

Given that the pH increased by 0.6 units after adding 'y g' of the salt, we can set up two Henderson-Hasselbalch equations for the scenarios when 'x g' and 'y g' of the salt have been added, respectively, and find the ratio of acetate concentrations. Before the addition, the pH is: \[ pH = pKa + \log\left(\frac{x}{[\text{HA}]}, \right) \] After the addition, the pH is increased by 0.6: \[ pH + 0.6 = pKa + \log\left(\frac{y}{[\text{HA}]}, \right) \] Since we know \(\log 3.98 = 0.6\), we can infer that the ratio of the concentrations of acetate ions is 3.98:1. Therefore, the ratio of the masses of sodium acetate added, x to y, is also 3.98:1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

pKa and pH Relationship
The pKa value of a weak acid is a constant that represents its acid dissociation constant, describing its ability to donate a proton. The relationship between pH and pKa is paramount for understanding where the equilibrium lies in the solution.

When pH equals pKa, there is a 1:1 ratio of acid to conjugate base, meaning the solution is perfectly buffered against pH changes at this point. The farther away the pH is from the pKa, the less buffer capacity remains. In our exercise, since the buffer's pH increases as we add more sodium acetate, understanding the pKa of acetic acid allows us to predict just how much addition of the conjugate base (sodium acetate) will alter the pH. This understanding is crucial for procedures such as titrations, where precision in pH is necessary.

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Most popular questions from this chapter

The dissociation constant of formic acid is \(0.00024\). The hydrogen ion concentration in \(0.002 \mathrm{M}-\mathrm{HCOOH}\) solution is nearly (a) \(6.93 \times 10^{-4} \mathrm{M}\) (b) \(4.8 \times 10^{-7} \mathrm{M}\) (c) \(5.8 \times 10^{-4} \mathrm{M}\) (d) \(1.4 \times 10^{-4} \mathrm{M}\)

Ascorbic acid (vitamin \(\mathrm{C}\) ) is a diprotic acid, \(\mathrm{H}_{2} \mathrm{C}_{6} \mathrm{H}_{6} \mathrm{O}_{6}\). What is the \(\mathrm{pH}\) of a \(0.10 \mathrm{M}\) solution? The acid ionization constants are \(K_{\mathrm{al}}=9.0 \times 10^{-5}\) and \(K_{\mathrm{a} 2}=1.6 \times 10^{-12} \cdot(\log 2=0.3, \log 3=0.48)\) (a) \(3.52\) (b) \(2.52\) (c) \(1.52\) (d) \(2.48\)

The addition of sodium acetate to acetic acid solution will cause (a) increase in its \(\mathrm{pH}\) value (b) decrease in its \(\mathrm{pH}\) value (c) no change in \(\mathrm{pH}\) value (d) change in \(\mathrm{pH}\) which cannot be predicted

For the indicator thymol blue, the value of \(\mathrm{pH}\) is \(2.0 \mathrm{when}\) half of the indicator is present in the unionized form. The percentage of the indicator in the unionized form in a solution of \(4.0\) \(\times 10^{-3} \mathrm{M}\) hydrogen ion concentration is (a) \(40 \%\) (b) \(28.6 \%\) (c) \(71.4 \%\) (d) \(60 \%\)

The buffer capacity \((\beta)\) for a weak acid (A) \(-\) conjugate base (B) buffer is defined as the number of moles of strong acid or base needed to change the \(\mathrm{pH}\) of \(1 \mathrm{~L}\) of solution by \(1 \mathrm{pH}\) unit, where \(\beta=\frac{2.303\left(C_{\mathrm{A}}+C_{\mathrm{B}}\right) K_{\mathrm{a}}\left[\mathrm{H}^{+}\right]}{\left(\left[\mathrm{H}^{+}\right]+K_{\mathrm{a}}\right)^{2}} .\) Under what condition will a buffer best resist a change in \(\mathrm{pH}\) ? (a) \(\mathrm{pH}=3 \mathrm{p} \mathrm{Ka}\) (b) \(2 \mathrm{pH}=\mathrm{p} \mathrm{Ka}\) (c) \(\mathrm{pH}=\mathrm{p} \mathrm{Ka}\) (d) \(\mathrm{pH}=2 \mathrm{p} \mathrm{Ka}\)

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