Chapter 5: Problem 48
Given the bond dissociation enthalpy of \(\mathrm{CH}_{3}-\mathrm{H}\) bond as \(103 \mathrm{kcal} / \mathrm{mol}\) and the enthalpy of formation of \(\mathrm{CH}_{4}(\mathrm{~g})\) as \(-18\) kcal/mol, find the enthalpy of formation of methyl radical. The dissociation energy of \(\mathrm{H}_{2}(\mathrm{~g})\) into \(\mathrm{H}\) (atoms) is 103 kcal/mol. (a) \(-33.5 \mathrm{kcal} / \mathrm{mol}\) (b) \(33.5 \mathrm{kcal} / \mathrm{mol}\) (c) \(18 \mathrm{kcal} / \mathrm{mol}\) (d) \(-9 \mathrm{kcal} / \mathrm{mol}\)
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