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At a constant temperature a gas occupies a volume of \(200 \mathrm{ml}\) at a pressure of \(0.720\) bar. It is subjected to an external pressure of \(0.900\) bar. What is the resulting volume of the gas? (a) \(160 \mathrm{ml}\) (b) \(320 \mathrm{ml}\) (c) \(80 \mathrm{~m} .\) (d) \(400 \mathrm{ml}\)

Short Answer

Expert verified
The resulting volume of the gas is 160 ml.

Step by step solution

01

Understanding Boyle's Law

This exercise involves understanding Boyle's Law, which states that for a given mass of an ideal gas at constant temperature, the volume of the gas is inversely proportional to its pressure. Mathematically, Boyle's Law can be expressed as P1 * V1 = P2 * V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume, respectively.
02

Setting up the equation

Using Boyle's Law, set up the equation using the initial and final pressures and volumes. The initial state has a volume (V1) of 200 ml and a pressure (P1) of 0.720 bar. The final pressure (P2) is 0.900 bar. We need to find the final volume (V2). The equation is P1 * V1 = P2 * V2.
03

Calculating the final volume

Rearrange the equation to solve for V2: V2 = (P1 * V1) / P2. Plug in the known values: V2 = (0.720 bar * 200 ml) / 0.900 bar. Perform the calculation to find the final volume.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Boyle's Law
Boyle's Law is fundamental to understanding how gases behave under pressure at a constant temperature. Named after the chemist Robert Boyle, who discovered the relationship in the 17th century, this law provides a simple mathematical way to predict how changes in pressure affect gas volume. According to Boyle's Law, pressure (\(P\text{ in bars, atm, etc.}\)) and volume (\(V\text{ in liters, milliliters, etc.}\)) of a gas are inversely proportional when temperature and amount of gas remain constant.

To visualize this, think of a syringe filled with air; as you push on the plunger, reducing the volume inside, the pressure of the air increases. Conversely, if you pull the plunger out, giving the air more space, the pressure drops. Boyle's Law can be expressed with the equation \[ P1 \times V1 = P2 \times V2 \], where \(P1\text{ and }\(V1\)\) are the initial pressure and volume, and \(P2\text{ and }\(V2\)\) are the final pressure and volume of the gas.
Ideal Gas Law
While Boyle's Law is a particular case focusing on constant-temperature scenarios, the Ideal Gas Law generalizes the relationships between pressure, volume, temperature, and the amount of gas. The Ideal Gas Law formula is given by \[ PV = nRT \], where \(P\) is the pressure, \(V\) is the volume, \(n\) is the number of moles of the gas, \(R\) is the universal gas constant, and \(T\) is the temperature in Kelvin.

Understanding the Ideal Gas Law is crucial for predicting the behavior of gases under a variety of conditions. It combines several gas laws, including Boyle's, Charles's, and Avogadro's laws, into one comprehensive equation. The versatility of the Ideal Gas Law makes it an essential tool for chemists and engineers to calculate changes in gas properties and to determine unknown variables in gas-based systems.
Pressure-Volume Relationship
Under the umbrella of Boyle's Law lies the concept of the pressure-volume relationship, a core principle when dealing with gases. This relationship tells us that for an ideal gas at constant temperature, as pressure increases, the volume decreases, and vice versa.

If you find yourself faced with a problem involving this relationship, remember to hold temperature constant and use the equation \[ P1 \times V1 = P2 \times V2 \] for your calculations. To apply it correctly, you need to ensure both volumes and pressures are in the same units. Also, be aware that real gases do not always behave exactly according to these simple laws, particularly at high pressures or low temperatures where they might deviate from ideal behavior.
Chemistry Problem Solving
Solving problems in chemistry—like applying Boyle's Law—requires a methodical approach. Start by identifying the given information and what you need to find out. In our exercise, we had initial and final pressures, and the initial volume, and we were looking to find the final volume. Understanding which formula to apply, in this case, Boyle's Law, is crucial.

Always rearrange equations to solve for the unknown before plugging in numbers; this can help prevent mistakes. For instance, by rearranging Boyle's Law to solve for the final volume \(V2\), we get \[ V2 = \frac{P1 \times V1}{P2} \]. Remember to carry units throughout your calculations, check your work at every step, and make sure your answer not only is mathematically correct but also makes sense physically. When tackling a chemistry problem, it's worthwhile to visualize the situation and ask if your results align with what you know about the behavior of gases.

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Most popular questions from this chapter

A box of 11 capacity is divided into two equal compartments by a thin partition, which is filled with \(2 \mathrm{~g}\) hydrogen and \(16 \mathrm{~g}\) methane, respectively. The pressure in each compartment is recorded as \(P\) atm. The total pressure when the partition is removed will be (a) \(P\) (b) \(2 P\) (c) \(P / 2\) (d) \(P / 4\)

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If the pressure of a certain amount of a gas increases by \(1 \%\) on heating by \(1^{\circ} \mathrm{C}\) at constant volume, its initial temperature must be (a) \(100 \mathrm{~K}\) (b) \(100^{\circ} \mathrm{C}\) (c) \(250 \mathrm{~K}\) (d) \(250^{\circ} \mathrm{C}\)

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